1 |
2.56 ms |
SELECT COUNT(*) AS dctrn_count FROM (SELECT DISTINCT id_0 FROM (SELECT r0_.id AS id_0, r0_.research_line AS research_line_1, r0_.sort AS sort_2, a1_.id AS id_3, a1_.researcher_id AS researcher_id_4, a1_.daisng_id AS daisng_id_5, a1_.bio AS bio_6, a1_.vigent AS vigent_7 FROM research_line r0_ INNER JOIN author_research_line a2_ ON r0_.id = a2_.research_line_id INNER JOIN author a1_ ON a1_.id = a2_.author_id WHERE a1_.vigent = 1 AND r0_.research_line LIKE ? ORDER BY r0_.sort ASC) dctrn_result) dctrn_table
Parameters: [
"%Earthquake-Resistant Engineering%"
]
SELECT COUNT(*) AS dctrn_count FROM (SELECT DISTINCT id_0 FROM (SELECT r0_.id AS id_0, r0_.research_line AS research_line_1, r0_.sort AS sort_2, a1_.id AS id_3, a1_.researcher_id AS researcher_id_4, a1_.daisng_id AS daisng_id_5, a1_.bio AS bio_6, a1_.vigent AS vigent_7 FROM research_line r0_ INNER JOIN author_research_line a2_ ON r0_.id = a2_.research_line_id INNER JOIN author a1_ ON a1_.id = a2_.author_id WHERE a1_.vigent = 1 AND r0_.research_line LIKE '%Earthquake-Resistant Engineering%' ORDER BY r0_.sort ASC) dctrn_result) dctrn_table;
|
2 |
2.02 ms |
SELECT DISTINCT id_0 FROM (SELECT DISTINCT id_0, sort_2 FROM (SELECT r0_.id AS id_0, r0_.research_line AS research_line_1, r0_.sort AS sort_2, a1_.id AS id_3, a1_.researcher_id AS researcher_id_4, a1_.daisng_id AS daisng_id_5, a1_.bio AS bio_6, a1_.vigent AS vigent_7 FROM research_line r0_ INNER JOIN author_research_line a2_ ON r0_.id = a2_.research_line_id INNER JOIN author a1_ ON a1_.id = a2_.author_id WHERE a1_.vigent = 1 AND r0_.research_line LIKE ?) dctrn_result_inner ORDER BY sort_2 ASC) dctrn_result LIMIT 4
Parameters: [
"%Earthquake-Resistant Engineering%"
]
SELECT DISTINCT id_0 FROM (SELECT DISTINCT id_0, sort_2 FROM (SELECT r0_.id AS id_0, r0_.research_line AS research_line_1, r0_.sort AS sort_2, a1_.id AS id_3, a1_.researcher_id AS researcher_id_4, a1_.daisng_id AS daisng_id_5, a1_.bio AS bio_6, a1_.vigent AS vigent_7 FROM research_line r0_ INNER JOIN author_research_line a2_ ON r0_.id = a2_.research_line_id INNER JOIN author a1_ ON a1_.id = a2_.author_id WHERE a1_.vigent = 1 AND r0_.research_line LIKE '%Earthquake-Resistant Engineering%') dctrn_result_inner ORDER BY sort_2 ASC) dctrn_result LIMIT 4;
|
3 |
0.88 ms |
SELECT r0_.id AS id_0, r0_.research_line AS research_line_1, r0_.sort AS sort_2, a1_.id AS id_3, a1_.researcher_id AS researcher_id_4, a1_.daisng_id AS daisng_id_5, a1_.bio AS bio_6, a1_.vigent AS vigent_7, a1_.user_id AS user_id_8 FROM research_line r0_ INNER JOIN author_research_line a2_ ON r0_.id = a2_.research_line_id INNER JOIN author a1_ ON a1_.id = a2_.author_id WHERE a1_.vigent = 1 AND r0_.research_line LIKE ? AND r0_.id IN (?) ORDER BY r0_.sort ASC
Parameters: [
"%Earthquake-Resistant Engineering%"
206
]
SELECT r0_.id AS id_0, r0_.research_line AS research_line_1, r0_.sort AS sort_2, a1_.id AS id_3, a1_.researcher_id AS researcher_id_4, a1_.daisng_id AS daisng_id_5, a1_.bio AS bio_6, a1_.vigent AS vigent_7, a1_.user_id AS user_id_8 FROM research_line r0_ INNER JOIN author_research_line a2_ ON r0_.id = a2_.research_line_id INNER JOIN author a1_ ON a1_.id = a2_.author_id WHERE a1_.vigent = 1 AND r0_.research_line LIKE '%Earthquake-Resistant Engineering%' AND r0_.id IN (206) ORDER BY r0_.sort ASC;
|
4 |
0.66 ms |
SELECT t0.id AS id_1, t0.email AS email_2, t0.roles AS roles_3, t0.password AS password_4, t0.name AS name_5, t0.last_name AS last_name_6, t0.rut AS rut_7, t0.sex AS sex_8, t0.photo AS photo_9, t10.id AS id_11, t10.researcher_id AS researcher_id_12, t10.daisng_id AS daisng_id_13, t10.bio AS bio_14, t10.vigent AS vigent_15, t10.user_id AS user_id_16 FROM `user` t0 LEFT JOIN author t10 ON t10.user_id = t0.id WHERE t0.id = ?
SELECT t0.id AS id_1, t0.email AS email_2, t0.roles AS roles_3, t0.password AS password_4, t0.name AS name_5, t0.last_name AS last_name_6, t0.rut AS rut_7, t0.sex AS sex_8, t0.photo AS photo_9, t10.id AS id_11, t10.researcher_id AS researcher_id_12, t10.daisng_id AS daisng_id_13, t10.bio AS bio_14, t10.vigent AS vigent_15, t10.user_id AS user_id_16 FROM `user` t0 LEFT JOIN author t10 ON t10.user_id = t0.id WHERE t0.id = 164;
|
5 |
0.90 ms |
SELECT t0.id AS id_1, t0.research_line AS research_line_2, t0.sort AS sort_3 FROM research_line t0 INNER JOIN author_research_line ON t0.id = author_research_line.research_line_id WHERE author_research_line.author_id = ?
SELECT t0.id AS id_1, t0.research_line AS research_line_2, t0.sort AS sort_3 FROM research_line t0 INNER JOIN author_research_line ON t0.id = author_research_line.research_line_id WHERE author_research_line.author_id = 167;
|